Required Mathematical Intelligence
Chapter 144 The Number of Dragonflies
Chapter 144 The Number of Dragonflies
There are 18 spiders, dragonflies, and cicadas in total, with 118 legs and 20 pairs of wings (spiders have 8 legs; dragonflies have 6 legs and two pairs of wings; cicadas have 6 legs and a pair of wings), how many dragonflies are there? Only?
[Answer: This is a question of development and change on the basis of chickens and rabbits in the same cage.Observing the characteristics of numbers, both dragonflies and cicadas have 6 legs, and only spiders have 8 legs.Therefore, we can start with the number of legs to find out the number of spiders.We assume that all three animals have 6 legs, then the total number of legs is 6×18=108 (pieces), and the difference is 118-108=10 (pieces), which must be caused by undercounting the number of legs of the spider.Therefore, there should be (118-108) ÷ (8-6) = 5 (only) spiders.
这样剩下的18-5=13(只)便是蜻蜓和蝉的只数。再从翅膀数入手,假设13只都是蝉,则总翅膀数1×13=13(对),比实际数少20-13=7(对),这是由于蜻蜓有两对翅膀,而我们只按一对翅膀计算所差,这样蜻蜓只数可求7÷(2-1)=7(只)。
Solution: ①Assuming that spiders also have 6 legs, how many legs do the three animals have? 6×18=108 (bars)
②有蜘蛛多少只?(118-108)÷(8-6)=5(只)
③How many dragonflies and cicadas are there? 18-5=13 (only)
④Assuming that the dragonfly is also a pair of wings, how many pairs of wings are there? 1×13=13 (pairs)
⑤蜻蜒多少只?(20-13)÷(2-1)=7(只)
Answer: There are 7 dragonflies. ]
(End of this chapter)
There are 18 spiders, dragonflies, and cicadas in total, with 118 legs and 20 pairs of wings (spiders have 8 legs; dragonflies have 6 legs and two pairs of wings; cicadas have 6 legs and a pair of wings), how many dragonflies are there? Only?
[Answer: This is a question of development and change on the basis of chickens and rabbits in the same cage.Observing the characteristics of numbers, both dragonflies and cicadas have 6 legs, and only spiders have 8 legs.Therefore, we can start with the number of legs to find out the number of spiders.We assume that all three animals have 6 legs, then the total number of legs is 6×18=108 (pieces), and the difference is 118-108=10 (pieces), which must be caused by undercounting the number of legs of the spider.Therefore, there should be (118-108) ÷ (8-6) = 5 (only) spiders.
这样剩下的18-5=13(只)便是蜻蜓和蝉的只数。再从翅膀数入手,假设13只都是蝉,则总翅膀数1×13=13(对),比实际数少20-13=7(对),这是由于蜻蜓有两对翅膀,而我们只按一对翅膀计算所差,这样蜻蜓只数可求7÷(2-1)=7(只)。
Solution: ①Assuming that spiders also have 6 legs, how many legs do the three animals have? 6×18=108 (bars)
②有蜘蛛多少只?(118-108)÷(8-6)=5(只)
③How many dragonflies and cicadas are there? 18-5=13 (only)
④Assuming that the dragonfly is also a pair of wings, how many pairs of wings are there? 1×13=13 (pairs)
⑤蜻蜒多少只?(20-13)÷(2-1)=7(只)
Answer: There are 7 dragonflies. ]
(End of this chapter)
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